鏡花水月-什麼是真?什麼是假?

題目:Toeplitz Matrix

難度:easy

問題:

A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.

Now given an M x N matrix, return True if and only if the matrix is Toeplitz.

Example 1:

Input:
matrix = [
  [1,2,3,4],
  [5,1,2,3],
  [9,5,1,2]
]
Output: True
Explanation:
In the above grid, the diagonals are:
"[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]".
In each diagonal all elements are the same, so the answer is True.

Example 2:

Input:
matrix = [
  [1,2],
  [2,2]
]
Output: False
Explanation:
The diagonal "[1, 2]" has different elements.

說明:

輸入陣列，如果斜線的數字都一樣，那就true

若不是，就出現false

所以我們只要跟斜邊比較數字就好囉~

以下是程式碼:

class Solution {
public:
    bool isToeplitzMatrix(vector<vector<int>>& matrix) {
        int i,j;
        for(i=0;i<matrix.size()-1;i++)
        {for(j=0;j<matrix[i].size()-1;j++)
            {
                  if(matrix[i][j]!=matrix[i+1][j+1])
                  return false;
            }
        }
      return true;  
    }
};